A car is moving eastwards with velocity 10 m/s. In 20 sec, the velocity changes to 10 m/s northwards. The average acceleration in this time

Q:A car is moving eastwards with velocity 10 m/s. In 20 sec, the velocity changes to 10 m/s northwards. The average acceleration in this time:

(A)1/√2 m s-2 towards N-W

(B)1/√2 ms-2 towards N-E

(C) 1/2 m s-2 towards N-W

(D) 1/2 ms-2 towards N

Solution: The change in velocity is

Δv = v2 – v1
= 10j – 10i
Δv has magnitude = 10√2 and directed due  N – W
Average acceleration =Δv ⁄Δt =10√2/20
= 1/√2 ms-2 and directed due N-W

Ans: (A)

Author: Rajesh Jha

QuantumStudy.com

Leave a Reply