A particle is dropped from a height h. Another particle which is initially at a horizontal distance …..

Q. A particle is dropped from a height h. Another particle which is initially at a horizontal distance d from the first is simultaneously projected with a horizontal velocity u and the two particles just collide on the ground ,then:

(a) \displaystyle d^2 = \frac{u^2 h}{2g}

(b) \displaystyle d^2 = \frac{2 u^2 h}{g}

(c) d = h

(d) g d2 = u2

Ans: (b)

Author: Rajesh Jha

QuantumStudy.com

Leave a Reply