A particle of mass m is revolving in a horizontal circle of radius r with a constant angular speed ω . The areal velocity of the particle is

Q: A particle of mass m is revolving in a horizontal circle of radius r with a constant angular speed ω . The areal velocity of the particle is
(A) r2 ω
(B) r2 θ
(C) r2ω/2
(D) rω2/2
Sol: Solution :
rotation
Areal velocity = dA/dt  ;
where A = area of the sector =r2θ/2
dA/dt = d(r2θ/2)/dt
½(r2)dθ/dt = r2ω/2

Author: Rajesh Jha

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