Prob 1. Two points A and B move on the +ve direction of x-axis and y-axis respectively, such that OA + OB = a. Show that the locus of the foot of the perpendicular from the origin O on the line AB is (x + y)(x2 + y2) = axy.
Sol.
Let the equation of AB be
….(1)
given, a + b = α ….(2)
now, mAB × mOM = -1
⇒ ah = bk ….(3)
from (2) and (3),
∴ from (1)
as it passes through (h , k)
⇒ (h + k) (h2 + k2) = αhk
∴ locus of (h , k) is (x + y) (x^2 + y^2) = αxy.