*Problem 2: What fraction of an ice cube floats in sea water ?*

* (given ρ*_{ice}* = 0.92 gm/cc , ρ*_{w}* =1.03 gm/cc. )*

*Solution :*

Ice cube is in the equilibrium. Therefore the net force acting on it is zero.

⇒ F_{b} – mg = 0

⇒ V’dg = Mg ,

where V’ = volume of the portion of ice cube immersed.

⇒ V’ dg = V Dg where V = volume of the total ice cube.

⇒ V’/V = D/d = 0.92/1.03 = 0.89.