Moment of inertia of a quarter disc having mass M and radius R about axis passing through centre of disc and perpendicular to plane is

Q: Moment of inertia of a quarter disc having mass m and radius R about axis passing through centre of disc and perpendicular to plane is
(A)I = mR²
(B)I = mR²/2
(C)I = mR²/4
(D)I = mR²/8

Solution: Moment of inertia (I) about z axis of a disc passing through centre of mass and perpendicular to the plane of disc is Iz = MR²/2
Since each quarter will have same moment of inertia (I)
4I= MR²/2
Iz = ¼MR²/2 = mR²/2
where ¼M = m = mass of each quarter of disc.

Author: Rajesh Jha

QuantumStudy.com for CBSE|IIT-JEE|NEET

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