# Average Speed & Average Velocity

♦Learn about : Average Speed , instantaneous speed , uniform speed ♦

(a) Average Speed:

Average speed:– Average speed of a particle is the ratio of total distance covered by a particle to the total time taken .

Average speed = total distance covered/Total time taken

A particle covers a distance by Δs = 10 m during a time interval Δt = 5 seconds.

Therefore $\displaystyle \frac{\Delta s}{\Delta t}$   is the ratio of distance covered Δs and the time interval Δt . This ratio is termed as time rate of change of distance.

It is common known as Speed of the particle over that particular time interval Δt.

That is why this speed is known as “Average Speed” denoted mathematically as

uav$\displaystyle \frac{\Delta s}{\Delta t}$

= 10/5
=2 m/s

Q.When a body covers first half distance with speed v1 and next half distance with speed v2 then find the average speed ?

Sol. Let the total distance = S

Total time taken , t = t1 + t

$\Large t = \frac{S}{2 v_1} + \frac{S}{2 v_2}$

$\LARGE Average Speed = \frac{Total Distance Travelled} {Total Time Taken}$

$\LARGE Average Speed = \frac{S}{ \frac{S}{2 v_1}+ \frac{S}{2 v_2} }$

$\LARGE Average Speed = \frac {2 v_1 v_2}{ v_1 + v_2 }$

(b) Instantaneous Speed:

If the particle is not moving with uniform speed, the average speed completed in the above section depends on the time interval Δt and the instant when it was computed.

It becomes necessary to define a quantity, called instantaneous speed which does not depend on the time interval Δt .

We take the time interval Δt as it becomes very small (infinitesimal) and the corresponding distance travelled Δs (which is also infinitesimal).-

Δt → 0 (infinitesimal time)

Δs → 0 (infinitesimal distance)

As Δt → 0 , Δs → 0

###### Instantaneous speed is equal to the magnitude of instantaneous velocity.

The ratio of the infinitesimal distance covered and the corresponding infinitesimal time yields a finite value. This finite value is known as the instantaneous speed of the particle.

(c) Uniform Speed

If the particle covers equal distances in equal intervals of time, it is said to be moving with uniform speed.

###### Student Notes:

# The slope of s-t graph at any time t gives the speed at that time t.

# The slope of x-t graph at any time t gives the instantaneous velocity (velocity at that time)

# For positive slope v is positive, for negative slope v is negative.

(a) Average Velocity

As the displacement of a particle changes with time, the ratio of change Δs of displacement vector s in a time interval Δt to that interval of time is known as time rate of change of displacement (vector) , this is known as the Velocity of the particle averaged over the time interval Δt or the average velocity,

$\displaystyle \vec {v_(av) } = \frac{\vec\Delta S}{\Delta t}$

(b) Instantaneous Velocity

The velocity of an   object at a particular instant or at a particular      point of its path is called instantaneous velocity of the object.

* Instantaneous speed is the magnitude of instantaneous velocity

The slope of the v-t graph gives the acceleration. If the slope is positive the acceleration is positive; if the slope is negative then the acceleration is negative (retardation or deceleration).

the area of a-t graph gives the change in velocity. If the area remains (above x- axes) positive, the change in velocity is positive and vice versa.

(c) Uniform Velocity :

A particle is said to be moving with uniform velocity if its velocity is independent of time.

Example : A particle moves in a straight line obeying the relation x = t (t-1) where x = displacement in m and t = time in sec. Find the velocity of the particle when its displacement is zero.

Solution:

x = t (t − 1)
= t2-t

If x = 0 , t ( t − 1) = 0

⇒ t = 0 and t = 1

The instantaneous velocity $\displaystyle v= \frac{dx}{dt}$ = $\displaystyle \frac{d(t^2 -t)}{dt}$ = 2t – 1

Putting t = 0 and t = 1 we obtain

Exercise 4 : Referring to the previous example ,

(a) What is the significance of positive and negative values of instantaneous velocities ?

(b) What are the distance covered and displacement during t = 2 sec. ?