An AC voltage source V = Vo sin ωt is connected across resistance R and capacitance C as shown….

Q: An AC voltage source V = V0 sin ωt is connected across resistance R and capacitance C as shown in figure. It is given that R = 1/ωC . The peak current is I0 . If the angular frequency of the voltage source is changed to ω /√3 , then the new peak current in the circuit is

Numerical

(a) I0 /2

(b) I0 /√2

(c) I0 /√3

(d) I0 /3

Ans: (b)