The radiation force due to source of power P on a perfectly reflecting surface will be

Q: The radiation force due to source of power P on a perfectly reflecting surface will be
(a) P/3c
(b) 2P/c
(c) P/2c
(d) P/c
Solution :(b)
E = m0c2
or , m0c = E/c
Change in momentum Δp = 2m0c = 2E/c
F = dp/dt = 2p/c (As dE/dt =p)

Author: Rajesh Jha

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