# When a car negotiates a curve, the normal force exerted on the inner & outer wheels are N1 & N2 respectively . Then N1 / N2 is

Q: When a car negotiates a curve, the normal force exerted on the inner & outer wheels are N1 & N2 respectively . Then N1 / N2 is
(A) = 1
(B) < 1
(C) > 1
(D) zero

Solution:

Referring to the free body diagram we obtain,
ΣFy= N1 + N2 – mg = 0
N1 + N2 = mg . . . (A)