When a car negotiates a curve, the normal force exerted on the inner & outer wheels are N1 & N2 respectively . Then N1 / N2 is

Q: When a car negotiates a curve, the normal force exerted on the inner & outer wheels are N1 & N2 respectively . Then N1 / N2 is
(A) = 1
(B) < 1
(C) > 1
(D) zero

Solution:
rotation
Referring to the free body diagram we obtain,
ΣFy= N1 + N2 – mg = 0
N1 + N2 = mg . . . (A)
Along radial, ΣFr = mar
fr = mv2/r . . . (B)
ΣtG = 0
N1d/2 + frh – N2d/2 = 0    . . . (C)
Using N2 – N1 = (2h/d)(mv2/r) & N2 = mg/2 + hmv2/dr
N1/N2 < 1

Author: Rajesh Jha

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