200 MeV of energy is obtained in the fission of one nucleus of U^235. A reactor is generating 1000 kW of power. The rate of nuclear fission in the reactor is

Q: 200 MeV of energy is obtained in the fission of one nucleus of U²³⁵. A reactor is generating 1000 kW of power. The rate of nuclear fission in the reactor is

(a) 1000

(b) 2 × 10⁸

(c) 3.125 × ¹⁶

(d) 931

Ans: (c)

Sol: $ Fission \; rate = \frac{P}{E} $

(100 × 10³)/(200 × 1.6 × 10^-13 )

= 3.125 × ¹⁶ sec^-1