Q: 50 ml. of a mixture of NH3 and H2 was completely decomposed by sparking into nitrogen and hydrogen. 40 ml of oxygen was then added and the mixture was sparked again. After cooling to the room temperature the mixture was shaken with alkaline pyro-gallol and a contraction of 6 ml. was observed. Calculate the % of NH3 in the original mixture.
Solution: Let the volume of NH3 be x ml
volume of H2 = (50– x) ml
NH3 → (1/2)N2 + (3/2)H2
Since 40 ml of O2 is added and sparked, it must have reacted with H2 to form liquid water. Moreover since 6 ml contraction occurs with alkaline pyrogallol, 34 ml is the volume of O2 used up.
Total volume of H2 is 68 ( 2 H2 + O2 → 2H2O)
(50–x) + (3/2)x = 68
50 + x/2 = 68 ; x = 36
NH3 = 72%