A 0.1 m long conductor carrying a current of 50 A is perpendicular to a magnetic field of 1.25 mT…

Q: A 0.1 m long conductor carrying a current of 50 A is perpendicular to a magnetic field of 1.25 mT. The mechanical power to move the conductor with a speed of 1 m/s is

Sol: Power P = Fv ; P = Bilv ; l = 0.1 m ; i = 50

B = 1.25 × 10-3 ; v = 1 m/sec ;

∴ p = B i l v

= 1.25 × 10-3 × 50 × 0.1 × 1

= 6.25 × 10-3

= 6.25 mW.