# A beam of electrons enter at right angles to uniform electric field with a velocity 3 x 107 m/s, E = 1800 v/m while travelling through a distance of 10 cm , the beam deflected by 2 mm then specific charge of electron is

Q: A beam of electrons enter at right angles to uniform electric field with a velocity 3 x 107 m/s, E = 1800
v/m while travelling through a distance of 10 cm , the beam deflected by 2 mm then specific charge of electron is

Sol: $\large t = \frac{x}{u} = \frac{0.1}{3 \times 10^7}$

$\large t = \frac{1}{3}\times 10^8 sec$

$\large y = \frac{1}{2} a t^2$

As , a = qE/m ;

$\large y = \frac{1}{2} (\frac{q}{m}E) t^2$

$\large 2 \times 10^{-3} = \frac{1}{2} (\frac{q}{m}\times 1800) (\frac{1}{3}\times 10^8)^2$

q/m = 2 × 1011 C/ kg.