Q:A block of mass m is moving with a constant acceleration a on a rough horizontal plane. If the coefficient of friction between the block and ground is μ , the power delivered by the external agent after a time t from the beginning is equal to
(A) ma2t
(B) μmgat
(C) μm(a + μg)gt
(D ) m(a + μg)at
Sol: Instantaneous power delivered = P = F→.v→ = F v
where, F – f = ma
F = f + ma
P = (f + ma) v
Put f = μmg
P = ( μmg + ma)v
P = m(a + μg).at