Q. A body is projected horizontally from the top of a tower with a velocity of 10 m/s. if it hits the ground at an angle 45°, the vertical component of velocity when it hits ground in m/s is
(a) 10
(b) 10√2
(c) 5√2
(d) 5
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Ans: (a)
$\displaystyle v_x = 10 m/s $
$\displaystyle tan\theta = \frac{v_y}{v_x} $
$\displaystyle tan45^o = \frac{v_y}{v_x} $
$\displaystyle v_y = v_x = 10 m/s$