Q. A body is projected horizontally from the top of a tower with a velocity of 10 m/s. if it hits the ground at an angle 45°, the vertical component of velocity when it hits ground in m/s is

(a) 10

(b) 10√2

(c) 5√2

(d) 5

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Ans: (a)

$\displaystyle v_x = 10 m/s $

$\displaystyle tan\theta = \frac{v_y}{v_x} $

$\displaystyle tan45^o = \frac{v_y}{v_x} $

$\displaystyle v_y = v_x = 10 m/s$