A body is projected with a velocity u. It passes through a certain point above the ground in t1 The time after which…..

Q. A body is projected with a velocity u. It passes through a certain point above the ground in t1 The time after which the body passes through the same point during the return journey

(a) $ \displaystyle (\frac{u}{g}-t_1^2)$

(b) $ \displaystyle 2(\frac{u}{g}-t_1)$

(c) $ \displaystyle 3(\frac{u^2}{g}-t_1)$

(d) $\displaystyle 3(\frac{u^2}{g^2}-t_1)$

Ans: (b)
Sol:
Time taken to reach maximum height = u/g

Time taken by body to reach maximum height after a certain point is =
$ \displaystyle \frac{u}{g} – t_1$
Time after which body passes the same point is
$ \displaystyle 2(\frac{u}{g}-t_1)$

Leave a Comment