Q. A body projected horizontally with a velocity ‘v’ from a height ‘h’ has a range ‘R’. With what velocity a body is to be projected horizontally from a height h/2 to have the same range?

(a) √2v

(b) 2v

(c) 6v

(d) 8v

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Ans: (a)

$ \displaystyle v_1 t_1 = v_2 t_2 $

$ \displaystyle v \sqrt{\frac{2h}{g}} = v_2 \sqrt{\frac{2h}{2g}}$