Q: A capacitor and resistor are connected with an AC source as shown in figure. Reactance of capacitor is XC = 3Ω and resistance of resistor is 4Ω . Phase difference between current I and I1 is [ tan-1 (3/4)= 37° ]
(a) 90°
(b) zero
(c) 53°
(d) 37°
Ans: (c)
Sol: $ \displaystyle I_1 = \frac{V}{R} $
$ \displaystyle I_1 = \frac{V}{4} $
$\displaystyle I_2 = \frac{V}{X_C} $
$ \displaystyle I_2 = \frac{V}{3} $
As I1 is in Phase with applied voltage but I2 is lead by 90° .
$\displaystyle tan\phi = \frac{V/3}{V/4} $
$ \displaystyle tan\phi = \frac{4}{3} $
$ \displaystyle \phi = tan^{-1}(\frac{4}{3}) $
φ = 53°