Q: A certain substance decays to 1/32 of its initial activity in 25 days. Calculate its half- life.
Sol: Since , $\large N = N_0 (\frac{1}{2})^n $ ;Where n = number of half life .
$\large \frac{N_0}{32} = N_0 (\frac{1}{2})^n $
n = 5
$\large 5 = \frac{25}{T_{1/2}}$
T1/2 = 5 days