Q: A charged particle (mass m charge q) moves along X-axis with velocity v_{o} . When it passes through origin it enters a region having uniform electric field $\vec{E} = -E\hat{j}$ which extends up to x = d . Equation of path of electron in the region x > d is

(a) $\displaystyle y = \frac{q E d}{m v_o^2}(x-d)$

(b) $\displaystyle y = \frac{q E d}{m v_o^2}(\frac{d}{2}-x)$

(c) $\displaystyle y = \frac{q E d}{m v_o^2} x $

(d) $\displaystyle y = \frac{q E d^2}{m v_o^2} x$

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Ans: (b)

Sol: