Q: A cooper rod of length 2 m is rotated with a speed of 10 rps, in a uniform magnetic field of 1 Tesla about a pivot at one end. The magnetic field is perpendicular to the plane of rotation. Find the emf induced across its ends

Sol: $\large e = \frac{1}{2} B \omega l^2 $

$\large e = \frac{1}{2} B (2\pi \nu) l^2 = \pi B \nu l^2 $

e = 3.14 × 1 × 10 × 2 × 2 = 125.6 volt.