# A disc is rolling (without slipping) on a horizontal surface. C is its centre and Q and P are two points equidistant from C…

Q:  A disc is rolling (without slipping) on a horizontal surface. C is its centre and Q and P are two points equidistant from C. Let vP, vQ and vC be the magnitude of velocities of points P, Q and C respectively, then

(a)vQ > vC > vP

(b)vQ < vC < vP

(c)vQ = vP , vC = (1/2) vP

(d)vQ < vC > vP

Ans: (a)

Sol: Velocity of any Point on the disc is v = r ω ; where r= distance of the point from bottom most point

AS , $\large r_Q > r_C > r_P$

Hence , $\large v_Q > v_C > v_P$