Q: A ladder of length 5 m is placed against a smooth wall as shown in figure. The coefficient of friction is μ between ladder and ground. What is the minimum value of μ , if the ladder is not to slip ?
(a) μ = 1/2
(b) μ = 1/4
(c) μ = 3/8
(d) μ = 5/8
Ans: (c)
Solution: Let normal reaction at B is N1 & at A is N2
For Translational Equilibrium
N1 = mg
f = N2
μ N1 = N2
μ mg = N2
μ = N2/mg —(i)
For rotational Equilibrium
N2 × OA = (mg)(2.5 cosθ)
Since, cosθ = 3/5 (from figure)
N2 × 4 = 3mg/2
N2/mg = 3/8
μ = 3/8 from(i)