Problem: A line through the origin divides parallelogram with vertices (10, 45), (10, 114), (28, 153) and (28, 84) into two congruent pieces. The slope of the line is

(A) 19/99

(B) 99/19

(C) 9/19

(D) 19/9

**Click to See Answer : **

Ans: (B)

Sol: Let AP = CQ = x

$\large \frac{45+x}{10} = \frac{153-x}{28} $

Þ 1260 + 28x = 1530 – 10x

x = 135/19

slope of PQ $\large = \frac{45+ \frac{135}{19}}{10}= \frac{99}{19} $

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