A metal oxide has the formula Z2O3. It can be reduced by hydrogen to give free metal and water…

Q: A metal oxide has the formula Z2O3. It can be reduced by hydrogen to give free metal and water. 0.1596g of the metal oxide requires 6 mg of hydrogen for complete reduction. The atomic weight of the metal is

(A) 27.9

(B) 159.6

(C) 79.8

(D) 55.8

Solution: Valency of metal in Z2O3 = 3

Z2O3 + 3H2 → 2Z + 3H2O

0.1596g of Z2O3 reacts with 6 mg of H2

1g H2 will react with g of Z2O3

equivalent weight of Z2O3 = 0.1596/0.006 = 26.6g

equivalent weight of Z2O3 = 26.6

= eq.wt. of Z + eq. wt. of = E + 8

E + 8 = 26.6

E = 18.6

Atomic weight of Z = 18.6 × 3 = 55.8