Q. A modern 200W sodium street lamp emits yellow light of wavelength 0.6mm. Assuming it to be 25% efficient in converting electrical energy to light, the number of photons of yellow light it emits per second is
(a) 62 × 1020
(b) 3 × 1019
(c) 1.5 × 1020
(d) 6 × 1018
Ans: (c)
Sol: Energy of photon , E= hc/λ
E = 6.6×10-34 × 3× 108/(0.6× 10-6)
E = 3.3× 10-19 J
Efficiency , η = P0/PI
25/100 = P0/200
P0 = 50 W
Number of photons emitted per sec
N = P0/E = 50/3.3× 10-19 = 1.5× 1020