A particle executes simple harmonic motion between x =-A and x =+A. The time taken for it to go…

Q: A particle executes simple harmonic motion between x =-A and x =+A. The time taken for it to go from O to A/2 is T1 and to go from A/2 to A is T2. Then

(a)T1 < T2

(b)T1 > T2

(c)T1 = T2

(d)T1 = 2 T2

Ans: (a)

Sol: In S.H.M velocity also oscillates simple harmonically . Speed at extreme position is minimum & at mean position it is maximum . Therefore speed of particle decreases from mean position to extreme position . The time taken for it to go from O to A/2 is less than time taken for it to go from A/2 to A . Hence T1 < T2