Q: A particle executes simple harmonic motion between x =-A and x = +A. The time taken for it to go from O to A/2 is T_{1} and to go from A/2 to A is T_{2}. Then

(a)T_{1} < T_{2}

(b)T_{1} > T_{2}

(c)T_{1} = T_{2}

(d)T_{1} = 2 T_{2}

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Ans: (a)

Sol: In S.H.M velocity also oscillates simple harmonically . Speed at extreme position is minimum & at mean position it is maximum . Therefore speed of particle decreases from mean position to extreme position . The time taken for it to go from O to A/2 is less than time taken for it to go from A/2 to A . Hence T

_{1}< T_{2}