# A particle is moving on a circular path. The angle turned by radius vector is θ = θ0 (1 – e^- t/3), where θ is in radian and t is in second. The angular acceleration at t = 0 is

Q: A particle is moving on a circular path. The angle turned by radius vector is $\theta = \theta_0 (1-e^{-t/3})$ , where θ is in radian and t is in second. The angular acceleration at t = 0 is