A particle is moving on a circular path. The angle turned by radius vector is θ = θ0 (1 – e^- t/3), where θ is in radian and t is in second. The angular acceleration at t = 0 is

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Q: A particle is moving on a circular path. The angle turned by radius vector is $\theta = \theta_0 (1-e^{-t/3})$ , where θ is in radian and t is in second. The angular acceleration at t = 0 is

(a) 1/3 rad/s2

(b) -1/9 rad/s2

(c) 10 rad/s2

(d) -1/6 rad/s2

Ans: (b)

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