Q: A particle moves in a straight line with a constant acceleration. It changes its velocity from 10 ms–1 to 20 ms–1 while passing through a distance 135 m in t sec. The value of t is
(a) 10
(b) 1.8
(c) 12
(d) 9
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Ans: (d)
Sol: Acceleration, a = (20-10)/t = 10/t
Using ,
$ \displaystyle v^2 = u^2 + 2 a s$
Sol: Acceleration, a = (20-10)/t = 10/t
Using ,
$ \displaystyle v^2 = u^2 + 2 a s$
$\displaystyle 20^2 = 10^2 + 2 (10/t) \times 135 $