# A particle of mass m is projected with velocity v at an angle θ with the horizontal. Its angular momentum about the point of….

Q: A particle of mass m is projected with velocity v at an angle θ with the horizontal. Its angular momentum about the point of projection when it is at the highest point of its trajectory.

(a) $\displaystyle \frac{m v^3 sin^2\theta cos\theta }{2 g}$

(b) $\displaystyle \frac{m v^3 sin^2\theta cos\theta }{ g}$

(c) $\displaystyle \frac{m v^2 sin^2\theta cos\theta }{2 g}$

(d) $\displaystyle \frac{m v^2 sin^2\theta cos\theta }{4 g}$

Ans: (a)