Q: A player caught a cricket ball of mass 150 gm moving at the rate of 20 m/sec. If the catching process be completed in 0.1 sec the force of the blow exerted by the ball on the hands of player is
(a) 0.3 N
(b) 30 N
(c) 300 N
(d) 3000 N
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Ans: (b)
Sol: Force = change in momentum per sec
$ \displaystyle F = \frac{150\times 10^{-3} \times 20}{0.1} $
F = 30 N