A projectile has the maximum range of 500 m. if the projectile is now thrown up on an inclined plane of 30° with the same speed…

Q: A projectile has the maximum range of 500 m. if the projectile is now thrown up on an inclined plane of 30° with the same speed, what is the distance covered by it along the inclined plane ?

Sol: $\large R_{max} = \frac{u^2}{g}$

$\large 500 = \frac{u^2}{g}$

$\large u^2 = 500 g $

$\large v^2 = u^2 + 2as $

$\large 0 = 500 g + 2(-gsin30^o)s $

s = 500 m