Q: A thermodynamic process is shown in figure. The pressures and volumes corresponding to some points in the figure are
PA = 3 × 104 Pa VA = 2 × 10-3 m³
PB = 8 × 104 Pa VD = 5 × 10-3 m³
In the process AB, 600 J of heat is added to the system and in process BC, 200 J of heat is added to the system. The change in internal energy of the system in process AC is
(a) 560 J
(b) 800 J
(c) 60 J
(d) 640 J
Ans: (a)
Sol: In going from A to C via B,
ΔQ = 600 + 200 = 800 J.
ΔW = WAB + WBC
=0+PB (BC)
=8×104×(VD-VA )
= 8×104 (5×10-3-2×10-3 ) = 240 J
ΔU =ΔQ -ΔW
= 800-240=560 J