An alpha nucleus of energy 1/2mv^2 bombards a heavy nuclear target of charge Ze. Then the distance of closest approach for the alpha nucleus will be proportional to

Q: An alpha nucleus of energy $\frac{1}{2}mv^2$ bombards a heavy nuclear target of charge Ze. Then the distance of closest approach for the alpha nucleus will be proportional to

(a) 1/m

(b) 1/v⁴

(c) 1/ Ze

(d) v²

Ans: (a)