Q: An ideal gas is subjected to cyclic process involving four thermodynamics states, the amount of heat (Q) and work (W) involved in each of these states :
Q1 = 6000 J, Q2 = – 5500 J; Q3 = – 3000 J; Q4 = 3500 J ; W1 = 2500 J; W2 = – 1000 J; W3 = – 1200 J; W4 = x J . The ratio of the net work done by the gas to the total heat absorbed by the gas is η . The values of x and η respectively are
(a) 500 ; 7.5%
(b) 700 ; 10.5%
(c) 1000 ; 21%
(d) 1500 ; 15%
Ans: (b)
Sol: In cyclic process
Q1 + Q2 + Q3 + Q4 = W1 + W2 + W3 + W4
6000 – 5500 – 3000 + 3500 = 25 00 – 1000 – 1200 + x
x = 700 J
∆Qcyclic = ∆Wcyclic = 1000 J
$\large \eta = \frac{\Delta W_{cyclic}}{Heat Supplied} = \frac{1000}{Q_1 + Q_4}$
$\large \eta = \frac{1000}{6000 + 3500} $
$\large \eta = \frac{10}{95} = \frac{10}{95} \times 100 $
= 10.5 %