Q: An indicator of 3 H is connected to a battery of emf 6 V through a resistance of 100 Ω. Calculate the time constant. What will be the maximum value of current in the circuit ?

Sol: Give that L = 3H , E = 6V , R = 100 Ω

Time Constant $\large \tau = \frac{L}{R}$

$\large \tau = \frac{3}{100}$

= 0.03 sec

Maximum Current $\large I_0 = \frac{E}{R} $

$\large I_0 = \frac{6}{100} $

= 0.06 volt