Q. Calculate the electric field in a copper wire of cross-sectional area 2 mm2 carrying a current of 1A . The resistivity of copper ρ = 1.7 x 10-8 ohm-m
(a) 8.5 mvm-1
(b) 8 mvm-1
(c) 9 mvm-1
(d) 7 mv/m
Ans: (a)
Resistance $ \displaystyle R = \rho \frac{L}{A} $
$ \displaystyle L = \frac{R A}{\rho} $
Since V = IR and V = EL
$ \displaystyle E = \frac{V}{L} = \frac{I R}{L} $
$ \displaystyle E = \frac{I R}{\frac{R A}{\rho}} $
$ \displaystyle E = \frac{I \rho}{A} $