Q: Calculate the energy released by fission from 2 g of (_{92}U^{235}) in kWh . Given that the energy released per

fission in 200 MeV.

Sol: Mass of uranium = 2 g

Energy released per fission = 200 MeV

= 200 × 10^{6} × 1.6 × 10^{-19} = 3.2 × 10^{-11} J

Number of atoms in 2 gram of uranium is n = (2 × 6.023 × 10^{23})/235 = 5.125 × 10^{21} atoms

Total energy released = No. of atoms x energy released per fission

= 5.125 × 10^{21} × 3.2 10^{-11} = 16.4 × 10^{10} J

Energy in Kwh = (16.4 × 10^{10})/(36 × 10^{5} ) Kwh

= 0.455 × 10^{5} kwh = 4.55 × 10^{4} kwh.