Q: Calculate the energy released by fission from 2 g of (92U235) in kWh . Given that the energy released per fission in 200 MeV.
Click to See Answer :
Sol: Mass of uranium = 2 g
Energy released per fission = 200 MeV
= 200 × 106 × 1.6 × 10-19 = 3.2 × 10-11 J
Number of atoms in 2 gram of uranium is n = (2 × 6.023 × 1023)/235 = 5.125 × 1021 atoms
Total energy released = No. of atoms x energy released per fission
= 5.125 × 1021 × 3.2 10-11 = 16.4 × 1010 J
Energy in Kwh = (16.4 × 1010)/(36 × 105 ) Kwh
= 0.455 × 105 kwh = 4.55 × 104 kwh.