Q: Calculate the energy released by the fission 1 g of (U235)in joule, given that the energy released per fission in 200 MeV. (Avogadro’s number = 6.023 × 1023)
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Ans: 8.202 × 1010 J
Sol: The number of atoms in 1 g of U235= (Avogadro’s number)/(Mass number)= (6.023 × 10^23)/235 = 2.563 × 1021
Energy released per fission = 200 MeV
= 200 × 106 × 1.6 × 10-19
= 3.2 × 10-11 J
Energy released by 1 g of U235
= Number of atoms × energy released per fission
= 2.563 × 1021 × 3.2 × 10-11 J
= 8.202 × 1010 J