Q: Calculate the energy released by the fission 1 g of (U^{235})in joule, given that the energy released per fission in 200 MeV. (Avogadro’s number = 6.023 × 10^{23})

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Ans: 8.202 × 10

^{10}JSol: The number of atoms in 1 g of U

^{235}= (Avogadro’s number)/(Mass number)= (6.023 × 10^23)/235 = 2.563 × 10^{21}Energy released per fission = 200 MeV

= 200 × 10^{6} × 1.6 × 10^{-19}

= 3.2 × 10^{-11} J

Energy released by 1 g of U^{235}

= Number of atoms × energy released per fission

= 2.563 × 10^{21} × 3.2 × 10^{-11} J

= 8.202 × 10^{10} J