Q: Calculate the energy released by the fission 1 g of (U^{235})in joule, given that the energy released per fission in 200 MeV. (Avogadro’s number = 6.023 × 10^{23})

Sol: The number of atoms in 1 g of U^{235}

= (Avogadro’s number)/(Mass number)= (6.023 × 10^23)/235 = 2.563 × 10^{21}

Energy released per fission = 200 MeV

= 200 × 10^{6} × 1.6 × 10^{-19} = 3.2 × 10^{-11} J

Energy released by 1 g of U^{235}

= Number of atoms × energy released per fission

= 2.563 × 10^{21} × 3.2 × 10^{-11} J

= 8.202 × 10^{10} J.