A body of mass m at rest is subjected to a constant force F for time t. The kinetic energy at time t is given by

Q: A body of mass m at rest is subjected to a constant force F for time t. The kinetic energy at time t is given by

(a) F2t2 /2m

(b) F2t2 /3m

(c) 2 F2t2/m

(d) F2t2/m

Ans: (a)

Solution: Acceleration , a = F/m

Applying , v = u + a t

$\displaystyle v = 0 + \frac{F}{m} t$

$\displaystyle v = \frac{F}{m} t$

Kinetic Energy , $\displaystyle K = \frac{1}{2} m v^2$

$\displaystyle K = \frac{1}{2} m (\frac{F}{m} t)^2$

$\displaystyle K = \frac{F^2 t^2}{2 m}$

Two bodies of masses m and 4m have equal kinetic energy. What is the ratio of their momentum ?

Q: Two bodies of masses m and 4m have equal kinetic energy. What is the ratio of their momentum?

(a)1 : 4

(b) 1 : 2

(c)1 : 1

(d) 2 : 1

Ans: (b)

Sol: As Kinetic Energy $\displaystyle K = \frac{p^2}{2 m}$ ; p = Linear Momentum

K.E1 = K.E2

$\displaystyle \frac{p_1^2}{2 m} = \frac{p_2^2}{2 \times 4 m}$

$\displaystyle \frac{p_1^2}{p_2^2} = \frac{1}{4}$

$\displaystyle \frac{p_1}{p_2} = \frac{1}{2}$

An electron, a proton, a deutron and an  α-particle have same linear momenta. Which one of them possesses least kinetic energy ?

Q: An electron, a proton, a deutron and an  α-particle have same linear momenta. Which one of them possesses least kinetic energy ?

(a) Electron

(b) Proton

(c) Deutron

(d)  α-particle

Ans: (d)

Sol: The relation between K.E & Linear Momentum is

$\displaystyle K = \frac{p^2}{2 m}$ ; p = Linear momentum

$\displaystyle K \propto \frac{1}{m}$ ; As p = constant

Since α-particle has larger mass , hence it has least kinetic energy .

A gun of mass M fires a bullet of mass m with maximum speed v. Given that m < M .The kinetic energy of the gun will be

Q: A gun of mass M fires a bullet of mass m with maximum speed v. Given that m < M .The kinetic energy of the gun will be

(a) 1/2 mv2

(b) 1/2 Mv2

(c) more than 1/2 mv2

(d) less than 1/2 mv2

Ans: (d)

Sol: $\displaystyle 0 = m \vec{v} + M \vec{v_1}$

$v_1 = – \frac{m}{M} v$

Kinetic energy of the gun will be

$K.E = \frac{1}{2} M v_1^2$

$K.E = \frac{1}{2} M (\frac{m}{M} v)^2$

$K.E = \frac{1}{2 M} m^2 v^2$

$K.E = \frac{m}{M} ( \frac{1}{2 } m v^2 ) < \frac{1}{2 } m v^2$

Two bodies A and B and having masses m and M respectively possess same momenta. Given that M > m. If EA and EB be their kinetic energies, then which of the following statement is true ?

Q:  Two bodies A and B and having masses m and M respectively possess same momenta. Given that M > m . If EA and EB be their kinetic energies , then which of the following statement is true ?

(a) EA = EB

(b) EA <  EB

(c) EA > EB

(d) It cannot be predicted.

Ans: (c)

$\displaystyle E_A = \frac{p^2}{2 m}$

$\displaystyle E_B = \frac{p^2}{2 M}$

$\displaystyle \frac{E_A}{E_B} = \frac{M}{m} > 1$

EA > EB