Q: A planet moving around sun sweeps area A1 in 2 days, A2 in 3 days and A3 in 6 days. Then the relation between A1, A2 and A3 is
(a) 3A1 = 2A2 = A3
(b) 2A1 = 3A2 = 6A3
(c) 3A1 = 2A2 = 6A3
(d) 6A1 = 3A2 = 2A3
Click to See Answer :
$\displaystyle \frac{dA}{dt} = constant$
$\displaystyle \frac{A_1}{2} = \frac{A_2}{3} = \frac{A_3}{6} $
On multiplying by 6 ,
A1 = 2A2 = A3