Volume Strength of H2 O2

Volume Strength of $H_2 O_2$

x  volume of H2O2 means x litre of O2 is liberated by 1 litre of H2O2 on decomposition

2H2O2 → 2H2O + O2

$68 gm   \quad \quad \quad   22. 4 lit  $   at STP

22.94lit (at STP) of O2 is given by 68 gm of H2O2

x litre of O2 is released from $ \frac{68 x}{22.4} $  gm of H2O2  $= \frac{17 x}{5.6}$

x lit of O2 is given by $= \frac{68 x}{22.4} = \frac{17 x}{5.6} $  (strength)

Strength, $\large  S   = \frac{17 x}{5.6} $

$\large Normality , N = \frac{S}{E} = \frac{17 x}{5.6 \times 34/2} = \frac{x}{5.6}$

$\large x = N \times 5.6$

$\large Molarity = \frac{1}{2}Normality = \frac{x}{11.2}$

Also Read :

→ Mole Concept & Principle of Atom Conservation
→ Gravimetric Analysis
→ Oxidation and Reduction
→ Balancing Redox Equations
→ Volumetric Analysis
→ Law of Equivalence
→ ‘ n ‘ Factor
→ Applications of the Law of Equivalence : Simple titration , Back titration
→ Double titration

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