Volume Strength of $H_2 O_2$

x volume of H_{2}O_{2} means x litre of O_{2} is liberated by 1 litre of H_{2}O_{2} on decomposition

2H_{2}O_{2 } → 2H_{2}O + O_{2}

$68 gm \quad \quad \quad 22. 4 lit $ at STP

22.94lit (at STP) of O_{2} is given by 68 gm of H_{2}O_{2}

x litre of O_{2} is released from $ \frac{68 x}{22.4} $ gm of H_{2}O_{2} $= \frac{17 x}{5.6}$

x lit of O_{2} is given by $= \frac{68 x}{22.4} = \frac{17 x}{5.6} $ (strength)

Strength, $\large S = \frac{17 x}{5.6} $

$\large Normality , N = \frac{S}{E} = \frac{17 x}{5.6 \times 34/2} = \frac{x}{5.6}$

$\large x = N \times 5.6$

$\large Molarity = \frac{1}{2}Normality = \frac{x}{11.2}$