Q: Determine the volume contraction of a solid copper cube, 10 cm on an edge, when subjected to a hydraulic pressure of 7.0 × 10^{6} Pa. (Bulk modulus for copper = 140 GPa )

Sol: Here; L= 10 cm =10^{-1} m; V= L^{3} =10^{-3} m^{3}

ΔP = 7.0 × 10^{6} Pa,K = 140 GPa = 140 × 10^{9} Pa

$\large K = \frac{\Delta P}{\frac{\Delta V}{V}}$

$\large \Delta V = \frac{\Delta P V}{K} $

$\large \Delta V = \frac{7 \times 10^6 \times 10^{-3}}{140 \times 10^9} $

= 5 × 10^{-8} m^{3}