Q: Determine the volume contraction of a solid copper cube, 10 cm on an edge, when subjected to a hydraulic pressure of 7.0 × 106 Pa. (Bulk modulus for copper = 140 GPa )
Sol: Here; L= 10 cm =10-1 m; V= L3 =10-3 m3
ΔP = 7.0 × 106 Pa,K = 140 GPa = 140 × 109 Pa
$\large K = \frac{\Delta P}{\frac{\Delta V}{V}}$
$\large \Delta V = \frac{\Delta P V}{K} $
$\large \Delta V = \frac{7 \times 10^6 \times 10^{-3}}{140 \times 10^9} $
= 5 × 10-8 m3