Q. Difference between nth and (n + 1)th Bohr’s radius of hydrogen atom is equal to (n – 1)th Bohr’s radius. The value of n is
(a) 1
(b) 2
(c) 3
(d) 4
Ans: (d)
Sol: rn ∝ n2
rn+1 ∝ (n+1)2
rn-1 ∝ (n-1)2
A/c to question ,
(n+1)2 – n2 = (n-1)2
2n + 1 = n2 – 2n +1
n2 – 4n = 0
n(n-4) = 0
n = 4