For a transistor , the current amplification factor is 0.8 . The transistor is connected in common emitter configuration . The change in collector current when the base current changes by 6 mA is

Q: For a transistor , the current amplification factor is 0.8 . The transistor is connected in common emitter configuration . The change in collector current when the base current changes by 6 mA is

(a) 4.8 mA

(b) 6 mA

(c) 8 mA

(d) 24 mA

Ans: (d)

Sol: Here , α = 0.8

$\large \beta = \frac{\alpha}{1-\alpha}$

$\large \beta = \frac{0.8}{1-0.8} = 4 $

$\large \beta = \frac{\Delta I_c}{\Delta I_b}$

$\large 4 = \frac{\Delta I_c}{6}$

ΔIc = 24 mA