Q: For a transistor , the current amplification factor is 0.8 . The transistor is connected in common emitter configuration . The change in collector current when the base current changes by 6 mA is
(a) 4.8 mA
(b) 6 mA
(c) 8 mA
(d) 24 mA
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Ans: (d)
Sol: Here , α = 0.8
$\large \beta = \frac{\alpha}{1-\alpha}$
$\large \beta = \frac{0.8}{1-0.8} = 4 $
$\large \beta = \frac{\Delta I_c}{\Delta I_b}$
$\large 4 = \frac{\Delta I_c}{6}$
ΔIc = 24 mA