# Force 3i + 6 j -2k N acts on a particle of mass 2 kg and displaces it from 4i + 2 j – 12 k m to 10 i + 5 j + 6 k m . The work done is

Q: Force $3 \hat{i} + 6 \hat{j} – 2 \hat{k}$  N acts on a particle of mass 2 kg and displaces it from $4 \hat{i} + 2 \hat{j} – 12 \hat{k}$  m to $10 \hat{i} + 5 \hat{j} + 6 \hat{k}$ m . The work done is

(a) 144 J

(b) 72 J

(c) 36 J

(d) 0 J

Ans: (d)