Q: Force $ 3 \hat{i} + 6 \hat{j} – 2 \hat{k} $ N acts on a particle of mass 2 kg and displaces it from $ 4 \hat{i} + 2 \hat{j} – 12 \hat{k} $ m to $ 10 \hat{i} + 5 \hat{j} + 6 \hat{k} $ m . The work done is
(a) 144 J
(b) 72 J
(c) 36 J
(d) 0 J
Ans: (d)