Q: Four particles of equal masses m move along a circle of radius R under the action of their mutual gravitational attraction. The speed of each particle. (a) $ \displaystyle \frac{1}{2}\sqrt{(2\sqrt2 +1)\frac{Gm}{R}} $ (b) $ \displaystyle \sqrt{(\sqrt2 +1)\frac{Gm}{R}} $ (c) $ \displaystyle \sqrt{(2\sqrt2 +1)\frac{Gm}{R}} $ (d) $ \displaystyle \frac{1}{2}\sqrt{(\sqrt2 +1)\frac{Gm}{R}} $ Ans: (a) Also Read :Two particles of equal mass go round a circle of radius R under the action of their mutual…Four particles, each of mass M and equidistant from each other, move along a circle of radius R…Two particles A and B initially at rest, move towards each other, under mutual force of…Three objects, each of mass m are at the vertices of an equilateral triangle and these vertices are…Two bodies of different masses of 2 kg and 4 kg are moving with velocities 20 m/s and 10 m/s towards…Two masses m1 and m2 (m1 < m2) are released from rest form a finite distance. They starts moving…Two particle A and B initially at rest, move towards each other by mutual force of attraction. At…Two particles move in a uniform gravitational field with an acceleration g. At the initial moment…A particle of mass 4 m explodes into three pieces of masses m,m and 2m. The equal masses move along…Two particles of masses 1kg and 2kg are placed at a distance of 50 cm. Find the initial acceleration… Post navigation Two identical discs are positioned on a vertical axis as shown in figure. The bottom disc is rotating at angular velocity…. A semicircular wire has a length L and mass M. A particle of mass m is placed at the centre of the circle……