Q: How much (U235) is consumed in a day in an atomic power house operating at 400 MW, provided the whole of mass U235 is converted into energy ?
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Sol: Powder = 400 MW = 400 x 106 W;
time = 1 day = 86, 400 s.
Energy produced , E = powder × time = 400 × 106 × 86,400 = 3.456 × 1013 J.
As the whole of mass is converted into energy, by Einstein’s mass-energy relation.
Einstein’s mass – energy relation.
E = m c2
E/c2 = (3.456 × 1013)/(3 × 108)2
= 3.84 × 10-4 kg = 0.384 g