How much (U235) is consumed in a day in an atomic power house operating at 400 MW, provided the whole of mass U235 is converted into energy ?

Q: How much (U235) is consumed in a day in an atomic power house operating at 400 MW, provided the
whole of mass U235 is converted into energy ?

Sol: Powder = 400 MW = 400 x 106 W;

time = 1 day = 86, 400 s.

Energy produced , E = powder × time = 400 × 106 × 86,400 = 3.456 × 1013 J.

As the whole of mass is converted into energy, by Einstein’s mass-energy relation.

Einstein’s mass – energy relation.

E = m c2

E/c2 = (3.456 × 1013)/(3 × 108)2

= 3.84 × 10-4 kg = 0.384 g