If I1 is the moment of inertia of a thin rod about an axis perpendicular to its length and passing through its centre of mass and l2 is the moment of inertia of the ring formed by the same rod about an axis tangent to the ring and perpendicular to the plane of the ring. Then find the ratio I1/I2.

Q: If I1 is the moment of inertia of a thin rod about an axis perpendicular to its length and passing through its centre of mass and l2 is the moment of inertia of the ring formed by the same rod about an axis tangent to the ring and perpendicular to the plane of the ring. Then find the ratio I1/I2 .

(a) $\displaystyle \frac{\pi^2}{3} $

(b) $\displaystyle \frac{\pi^2}{6} $

(c) $\displaystyle \frac{\pi^2}{2} $

(d) $\displaystyle \frac{\pi^2}{5} $

Ans: (b)